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Overview

Polar form turns multiplication into angle addition and scaling. It is the fastest path for high powers.

Core Skills

Convert to Polar Form

Compute r=zr=|z| and θ=argz\theta=\arg z so z=r(cosθ+isinθ)z=r(\cos\theta+i\sin\theta).

Multiply and Divide

Multiply magnitudes and add arguments; divide magnitudes and subtract arguments.

Reduce Angles

Always reduce angles modulo 2π2\pi to keep arguments in a standard range.

Key Ideas

  • z=r(cosθ+isinθ)=reiθz = r(\cos\theta + i\sin\theta) = re^{i\theta}.
  • De Moivre: zn=rn(cosnθ+isinnθ)z^n = r^n(\cos n\theta + i\sin n\theta).
  • Multiply by adding arguments and multiplying magnitudes.

Worked Example

Compute (1+i)10(1+i)^{10}.

1+i=2eiπ/41+i = \sqrt{2}e^{i\pi/4}. Then (1+i)10=(2)10ei10π/4=25eiπ/2=32i(1+i)^{10} = (\sqrt{2})^{10} e^{i\cdot 10\pi/4} = 2^5 e^{i\pi/2} = 32i.

More Examples

Example 1: Power

Compute (2eiπ/3)4(2e^{i\pi/3})^4.

24ei4π/3=16(cos4π3+isin4π3)2^4 e^{i4\pi/3} = 16\left(\cos\frac{4\pi}{3}+i\sin\frac{4\pi}{3}\right).

Example 2: Product

If z1=3eiπ/6z_1=3e^{i\pi/6} and z2=2eiπ/4z_2=2e^{i\pi/4}, find z1z2z_1z_2.

6ei(π/6+π/4)=6ei5π/126e^{i(\pi/6+\pi/4)} = 6e^{i5\pi/12}.

Example 3: Division

Compute 4eiπ/22eiπ/3\frac{4e^{i\pi/2}}{2e^{i\pi/3}}.

2ei(π/2π/3)=2eiπ/62e^{i(\pi/2-\pi/3)} = 2e^{i\pi/6}.

Strategy Checklist

  • Convert to polar form before powering.
  • Add or subtract arguments correctly.
  • Reduce angles to a standard range.

Common Pitfalls

  • Using degrees in one step and radians in another.
  • Forgetting to reduce angles modulo 2π2\pi.
  • Mixing up magnitude and argument operations.

Practice Problems

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