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Overview

Polynomials appear often at AIME level. Learn how to relate roots and coefficients and how to build polynomials with given roots.

Key Ideas

  • If roots are r1,r2r_1, r_2, then x2(r1+r2)x+r1r2=0x^2-(r_1+r_2)x+r_1r_2=0.
  • If p(a)=0p(a)=0, then (xa)(x-a) is a factor of p(x)p(x).
  • Symmetric expressions often reduce via Vieta.

Core Skills

Use the Factor Theorem

Test small integer roots quickly and factor out (xa)(x-a) when p(a)=0p(a)=0.

Build a Polynomial

If roots are given, form (xri)\prod (x-r_i) and expand or leave factored as needed.

Use Vieta for Symmetric Sums

Compute r2+s2r^2+s^2 or 1/r+1/s1/r+1/s using r+sr+s and rsrs.

Worked Example

If rr and ss are roots of x25x+6=0x^2-5x+6=0, compute r2+s2r^2+s^2.

We have r+s=5r+s=5 and rs=6rs=6. Then r2+s2=(r+s)22rs=2512=13r^2+s^2=(r+s)^2-2rs=25-12=13.

More Examples

Example 1: Polynomial from Roots

Find the monic polynomial with roots 22 and 3-3.

(x2)(x+3)=x2+x6(x-2)(x+3)=x^2+x-6.

Example 2: Reciprocal Sum

If r+s=4r+s=4 and rs=3rs=3, find 1r+1s\frac{1}{r}+\frac{1}{s}.

r+srs=4/3\frac{r+s}{rs}=4/3.

Example 3: Factor Theorem

If p(x)=x34x2x+4p(x)=x^3-4x^2-x+4, show that x=1x=1 is a root and factor p(x)p(x).

p(1)=0p(1)=0, so (x1)(x-1) is a factor. Then p(x)=(x1)(x23x4)p(x)=(x-1)(x^2-3x-4).

Strategy Checklist

  • Test small integer roots first.
  • Use Vieta for symmetric expressions.
  • Keep polynomials factored when possible.

Practice Problems

StatusSourceProblem NameDifficultyTags
AIMEHard
Show TagsPolynomials, Vieta
AIMEVery Hard
Show TagsFactor Theorem

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